| Iterated Function Systems Larry Riddle |
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Koch Snowflake | ||||||||||
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Start with an equilateral triangle T. Scale T by a
factor of 1/3 and place 3 copies along each of the three sides of
T as illustrated in the diagram below to form a new image
S(1). Next scale T by a factor of 1/9 = (1/3)^2 and
place 12=4*3 copies along the sides of T(1) as illustrated to
form the image S(2). For the next iteration, take 48=4*12
copies of T scaled by a factor of 1/27=(1/3)^3 and place them
around the sides of S(2) to form the image S(3).
Continue this construction. The Koch Snowflake is the limiting image
of the construction.
The sequence of sets S(1), S(2), S(3), .... that are constructed this way form a Cauchy sequence in the Hausdorff metric, and the limit is the Koch snowflake. Here is a proof. Leslie Reid, Missouri State University, provided the following IFS code for the Koch snowflake. Use 12 maps. The first 6 consist of scaling by a factor of 1/3 and respective translations by (0,4), (-sqrt(3),1), (sqrt(3),1), (-2sqrt(3), -2), (0,-2), and (2sqrt(3),-2). The other 6 maps consist of scaling by a factor of 1/3, rotation by 180 degrees, and translation by the opposite of the vectors listed above. This produces the following image.
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The boundary of the snowflake consists of three copies of the Koch
curve placed around the three sides of the initial equilateral
triangle. It can be constructed by the following L-system:
Angle 60 | ||||||||||
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The Koch snowflake is also known as the Koch island.
The length of the boundary of S(n) at the nth iteration of the construction is 3*(4/3)^n*s, where s denotes the length of each side of the original equilateral triangle. Therefore the Koch snowflake has a perimeter of infinite length. The area of S(n) is | ||||||||||
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