Larry Riddle, Agnes Scott College

Construction

Animation

Begin with a line segment. As the first iteration, replace this
segment with three segments in a Z shape, each scaled by a ratio \({\bf{r}} = \frac{1}{{\sqrt 3 }}\). The middle segment makes an angle of 60° with the first and last segments.
Following along the original segment, we start the
first new segment to the left. For the second iteration, replace each
of the three segments with three new segments in the same motif, each scaled by
the ratio **r**. The new segments are placed to the left, then to
the right, and then to the left. Continue this
construction, always alternating the new segments between left and
right along the segments of the previous iteration. This generates
the "terdragon curve". The following figure shows the first three
iterations for this construction.

Fold a long narrow
sheet in thirds, folding the first third towards you and the last third away from you. Fold three times again in the same directions
(Example). Continue folding, always folding
in the same directions. After several folds, open the sheet so that
every fold is at 60deg; and view the sheet from the edge. In
general, *n* sets of folds produce an order-*n* dragon. The
following picture shows an order-2 dragon.

Function

System

Starting with an initial set that is a horizontal unit line segment, the construction shown above requires three copies of the segment, each scaled by a factor **r**. The first must be rotated by 30°, the second by −90°, and the last by 30°. The second and third segments must then be translated so that the path remains connected.

We see that

\[r = \frac{{1/2}}{{\cos {{30}^ \circ }}} = \frac{{\frac{1}{2}}}{{\frac{{\sqrt 3 }}{2}}} = \frac{1}{{\sqrt 3 }}\]

IFS

Animation

This yields the following IFS.

\({f_1}({\bf{x}}) = \left[ {\begin{array}{*{20}{c}}
{1/2} & { - \sqrt 3 / 6} \\
{\sqrt 3 / 6} & {1/2} \\
\end{array}} \right]{\bf{x}}\) |
scale by \(1/ \sqrt 3\), rotate by 30° |

\({f_2}({\bf{x}}) = \left[ {\begin{array}{*{20}{c}}
{ 0} & { \sqrt 3 /3} \\
{-\sqrt 3 /3} & { 0} \\
\end{array}} \right]{\bf{x}} + \left[ {\begin{array}{*{20}{c}}
1/2 \\
\sqrt 3 / 6 \\
\end{array}} \right]\) |
scale by \(1/ \sqrt 3\), rotate by −90° |

\({f_1}({\bf{x}}) = \left[ {\begin{array}{*{20}{c}}
{1/2} & { - \sqrt 3 / 6} \\
{\sqrt 3 / 6} & {1/2} \\
\end{array}} \right]{\bf{x}}+ \left[ {\begin{array}{*{20}{c}}
1/2 \\
-\sqrt 3 / 6 \\
\end{array}} \right]\) |
scale by \(1/ \sqrt 3\), rotate by 30° |

The terdragon consists of three self-similar pieces corresponding to the three functions in the IFS.

Angle 30

Axiom F

F —> +F−−−−F++++F−

Axiom F

F —> +F−−−−F++++F−

Dimension

The terdragon is self-similar with 3 non-overlapping copies of itself, each scaled by the factor
**r** < 1. Therefore the similarity dimension, **d**, of the
attractor of the IFS is the solution to

\[\sum\limits_{k = 1}^3 {{r^d}} = 1 \quad \Rightarrow \quad d = \frac{{\log (1/3)}}{{\log (1/\sqrt 3 )}} = 2\]

Properties

Three copies of the terdragon tile the plane. In addition to the regular terdragon, one copy must be rotated by 60° and the other by −60°. Click on each of the buttons in succession to see this tiling in the square below.

Six copies of the terdragon can be joined together at a common point at 60° angles.

The boundary of the terdragon is a fractal with dimension log(4)/log(3) = 1.26186 [Details].

The area of a terdragon with an initial segment of length b is equal to \(\dfrac{b^2}{2 \sqrt 3}\) [Details].

Three copies of the terdragon form a fudgeflake. The fudgeflake can also be formed by placing copies of the lower boundary of the terdragon around the three sides of an equilateral triangle (similar to the construction of the Koch snowflake). Copies of the fudgeflake will tile the plane (if you look at the tiling picture above, you can see the red/blue/green grouping of three terdragons that make up one fudgeflake). Click on the name for more details.

- Edgar, Gerald A.
*Measure, Topology, and Fractal Geometry*, Springer-Verlag, 1990. - Davis, Chandler and Donald J. Knuth. "Number representations
and dragon curves"
*J. Recreational Math.***3**(1970) 66-81 (Part 1), 133-149 (Part 2). Reprinted with extra addendum in*Selected Papers on Fun and Games*, Donald Knuth, CSLI Publications, 2011.