| Iterated Function Systems Larry Riddle |
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Area of the Koch Snowflake | ||||||||||
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The first observation is that the area of an equilateral triangle with side length a is
as we can determine from the following picture
The area of the initial triangle T is therefore
Area of first iteration:
Area of second iteration:
Area of third iteration:
By now the pattern should be clear. At the kth iteration we
add 3*4^(k-1) additional triangles of area
to the area S(k-1) to get the area of S(k). Hence after n iterations we get the area of S(n) to be
The sum inside the parentheses is the partial sum of a geometric series with ratio r = 4/9. Therefore the sum converges as n goes to infinity, so we finally obtain
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