In the left triangle, the black triangle can be placed in any of the three corners. Once that choice is made, however, the location of the black triangle in the right triangle must be chosen in a way to maintain the symmetry with respect to the vertical line. There are therefore only 3 possible choices for locating the black triangles among the three triangles in the pattern. These are shown below. Click on any of the images to toggle between the pattern and the corresponding triangle fractal.
Now as long as another transformation that is applied to a triangle does not change the location of the black triangle, the attractor will not change. For each pattern above, there are two allowable transformations for each of the three triangles that will preserve the symmetry. One of these transformations is the identity. The other is either 4, 5 or 6, the reflections across the altitudes.
Which reflection is allowed for a triangle depends on the location of the black triangle within that triangle. For example, in the pattern
the possible transformations are {1,5} for the left triangle, {1,4} for the middle triangle and {1,6} for the right triangle. There are therefore 8 different 3-digit sequences that will leave the black triangles in this pattern in the same location and thus produce the same fractal. These are shown below.
The same is true for each of the other 2 symmetric patterns. This accounts for 24 of the 216 possible 3-digit sequences.
To get a sense of why this works, first note that in reflecting the pattern horizontally, the left and right triangles will trade places. This is why the order of the sequence is reversed. Second, if F represents the iterated function system for the pattern (a,b,c) and if A is the attractor for that IFS, then T4(A) would represent the horizontal reflection of A, where T4 is the transformation corresponding to the horizontal reflection. Since F(A) = A and T4T4 is the identity transformation, we would have
T4FT4(T4(A)) = T4F(A) = T4(A).
This shows that T4(A) is the attractor (fixed point) for the IFS given by T4FT4.
According to the dihedral group multiplication table, we have
4•1•4 = 1
4•2•4 = 3
4•3•4 = 2
4•4•4 = 4
4•5•4 = 6
4•6•4 = 5
So for example, if we start with the sequence 251, its symmetric counterpart would be 163. These patterns and corresponding fractals are shown below.
251
163
Since the non-symmetric fractals can be grouped into pairs, there are essentially 96 different non-symmetric triangle fractals.
See a Gallery of all 99 triangle fractals.